VTABLE virtual function in derived class

[rahul8143]

hello,
what happens to VTABLE when base class has virtual function and
derived class does not override it? Does derived class also builds
VTABLE if it has no functions?
eg. if code is like this(only demo code)
class a{
public:
virtual void fun()
{
cout<<"Base class";
}
};
class dublic a
{
};

int main()
{
d obj;
return 0;
}

 

[Maxim Yegorushkin]

hello,
what happens to VTABLE when base class has virtual function and
derived class does not override it? Does derived class also builds
VTABLE if it has no functions?

Why do you care?

In a typical implementation vtables are generated one per class by a
compiler at compile stage and stored in a read only segment of your
binary. Thus, no runtime vtable building occurs. A class instance bears
only a pointer to its vtable. Upon entering a constructor compiler
injected code sets the vtable pointer to a proper vtable.

 

[rahul8143]

Why do you care?

In a typical implementation vtables are generated one per class by a
compiler at compile stage and stored in a read only segment of your
binary.

Does that mean if i have 3 classes base1, derived1, derived2 then
each one has VTABLE provided all are usinf virtual functions?

Thus, no runtime vtable building occurs. A class instance bears

that mean derived class also builds VTABLE at compile time then is
address od virtual function be same for base1 and derived1 if base1 has
virtual function and derived1 has no overridden function?

 

[Maxim Yegorushkin]

Does that mean if i have 3 classes base1, derived1, derived2 then
each one has VTABLE provided

Yes. A compiler may optimize out a vtable for a derived class if it
does not overload any virtual functions so that its base class's vtable
is fine.

all are usinf virtual functions?

Did not understand this part.

 

[Maxim Yegorushkin]

Maxim Yegorushkin wrote:

[]

Yes.

Well, I am wrong here when multiple inheritance comes in. You might
find this illuminating http://files.rsdn.ru/4539/cud94.htm