why a class can't access protected method from another class in thesame package,the method is interi

[junzhang1983]

package XX;
class A
{
protected void kk ();
}

package YY;
import XX.A;

class B extends A
{

}

package YY;
class C
{
public void zz()
{
kk(); //why can call B.kk()????
}
}



but if we modify as below:
package YY;
import XX.A;

class B extends A
{
protected void kk ()
{
super.kk();
}
}


why above modify can success?
3ks

 

[Hal Rosser]

package XX;
class A
{
protected void kk ();
}

package YY;
import XX.A;

class B extends A
{

}

package YY;
class C
{
public void zz()
{
kk(); //why can call B.kk()????
}
}

_________
Because protected keyword gives access to subclasses and other members of
the same package.
And class C is not a subclass and not in package XX.

but if we modify as below:
package YY;
import XX.A;

class B extends A
{
protected void kk ()
{
super.kk();
}
}


why above modify can success?
3ks

Because B is a subclass of A

 

[Lew]

This will not compile. Why does the comment refer to B.kk()? Class B is not
involved in the C invocation at all. C does not have a method kk().

 

[Roedy Green]

why above modify can success?

two things. Please use standard caps conventions when you write code,
especially lower case package names. See
http://mindprod.com/jgloss/codingconventions.html

It makes your code look extremely weird to an eye accustomed to
conformant code.

Next read up on what the various scopes are supposed to do.

See http://mindprod.com/jgloss/scope.html
http://mindprod.com/jgloss/protected.html