Why does this return fail to work while the other doesn't?

[The Cool Giraffe]

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;



Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));



Of course i have that char ch[10] and i'm returning
std:string from the method. I'm using VC++.NET compiler.

 

[Rolf Magnus]

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;



Now, i've tried to exchange those two for the one below but

the computer said no. Why?

It just said "no"? That's quite a useless error message.

return (std::string outPut (ch));

A variable definition has no value. You have to use a temporary:

return std::string(ch);

 

[Victor Bazarov]

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;



Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

Because you're trying to declare an object (named 'outPut') in
the return statement's expression. That is not allowed. You
need:

return std::string(ch);

which just creates a temporary [unnamed] object of type string
and returns its value.

Of course i have that char ch[10] and i'm returning
std:string from the method. I'm using VC++.NET compiler.

Compiler doesn't matter.

V

 

[Thomas Tutone]

I have these two line of code and they work as they're
supposed to.

std::string outPut (ch);

return outPut;

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

change that to:

return std::string(ch);

and all should be good.

Best regards,

Tom

 

[David Harmon]

On Tue, 13 Feb 2007 17:17:59 +0100 in comp.lang.c++, "The Cool Giraffe"

Now, i've tried to exchange those two for the one below but

the computer said no. Why?

return (std::string outPut (ch));

What is "output" doing there? You can't declare a variable just in the
middle of an expression.

return std::string(ch);

 

[The Cool Giraffe]

Thomas Tutone wrote/skrev/kaita/popisal/schreibt :

change that to:

return std::string(ch);

and all should be good.

Best regards,

Got it. Thanks to all.

 

[Alan Johnson]

It just said "no"? That's quite a useless error message.

I work with an IDL compiler which has only one error message:
"You used it wrong."