Why the following code does not compile ?

[Razvan]

Hi !




The following code does not compile:

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !




Regards,
Razvan

 

[Adam Maass]

Hi !




The following code does not compile:

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !

The addition is int arithmetic. The result of the addition is an int.


-- Adam Maass

 

[Paul Lutus]

Hi !




The following code does not compile:

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !

The operator "+" assumes integer operands in this case. Use:

bb = (byte) (bb + 5);

 

[Superdude]

Hi !




The following code does not compile:

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !




Regards,
Razvan

any mathematical operation is at minimum an int result unless any of the
operands are long, float, double, then the result is the highest bit size.

 

[Cid]

Hi !
The following code does not compile:

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !

You want to look up
5.6.2 Binary Numeric Promotion
in the Java Language Specification which you can freely read/download
from here:
http://java.sun.com/docs/books/jls/index.html

 

[ANOOP CHILKA]

try this....

byte bb = 7;
bb = (byte) (bb + ((byte) 5));

 

[Babu Kalakrishnan]

try this....

byte bb = 7;
bb = (byte) (bb + ((byte) 5));

or simply :

bb += 5;

The cast to (byte) is implicitly performed when you use the
+= operator.

BK

 

[Babu Kalakrishnan]

byte bb = 7;
bb = bb + ((byte) 5);

Since both operands are bytes there should be no problem, yet
there is a "possible loss of precision" !

Both operands being bytes does not mean that the result would fit into a
byte. (Try adding two bytes with values >= 64)

BK