wierd error.....help please.....

  • Thread starter John Pether (john@
  • Start date
J

John Pether (john@

have been working with a site and today started getting an error when uploaded page on the live server...everything works well locally...

The XML page cannot be displayed
Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.

--------------------------------------------------------------------------------
A name was started with an invalid character. Error processing resource 'http://www.bchandbook.com/kalamunda/cats.asp'. Line 3, Position 2

<%@LANGUAGE="VBSCRIPT" CODEPAGE="1252"%>
-^

the top of the page looks like this...

<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<%@LANGUAGE="VBSCRIPT" CODEPAGE="1252"%>

Any ideas how to get rid of this??? is drivin me mad....have been at it for an hour or two....





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J

John Pether (john@

??

this is an asp page made in dreamweaver mx?? It is not asp.net??

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C

Chris Barber

The @Language="VBScript" declaration is a server-side declaration that
defines the default script engine.

You can remove it if you know that your default script engine is VBScript
(ASP).

Chris.

John Pether said:
??

this is an asp page made in dreamweaver mx?? It is not asp.net??

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J

John Pether (john@

it wont let me see source...just says the xml file is unavailable for viewing

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B

Bob Barrows

John said:
it wont let me see source...just says the xml file is unavailable for
viewing

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Click to expand...

My mistake. I didn't realize you were dealing with a file. I thought you
were doing a response.write using contenttype = text/xml.

What happens if you just remove the <%Language... tag?
 
B

Bob Barrows

Bob said:
My mistake. I didn't realize you were dealing with a file. I thought
you were doing a response.write using contenttype = text/xml.

What happens if you just remove the <%Language... tag?
Click to expand...

Actuall, just move this tag to the top of the page, BEFORE the xml tags
begin.
 
M

Mark Schupp

You might check the versions of MSXML between the server that works and the
one that doesn't.

--
Mark Schupp
--
Head of Development
Integrity eLearning
Online Learning Solutions Provider
(e-mail address removed)
http://www.ielearning.com
714.637.9480 x17


John Pether said:
thankseveryone for trying to help but am still struggling with this one:(:(

The page is an asp page that displays a dynamic list. It is xhtml
Click to expand...
compliant and was made in dreamweaver mx.
I have pasted the full page below, basically it collects 2 sets of data
Click to expand...
from a sql server using stored procs on the sql server. These pages work
fine locally and I have just uploaded to another host and again they worked
fine, the only difference I can find betweeen the hosts that work and the
one that doesn't is that the one that is not working does not have the .net
framework installed, but as this is an asp page I am confused as to why that
would effect the page and give an xml error!!!!
<code>
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<%@language="vbscript" codepage="1252"%>

<!--#include file="../Connections/****.asp" -->
<%
Dim GetCategories__CatID
GetCategories__CatID = "1"
If (Request.QueryString("parentcatid") <> "") Then
GetCategories__CatID = Request.QueryString("parentcatid")
End If
%>
<%
Dim GetCategories
Dim GetCategories_numRows

Set GetCategories = Server.CreateObject("ADODB.Recordset")
GetCategories.ActiveConnection = MM_BCH_STRING
GetCategories.Source = "{call dbo.GetCategories(" +
Click to expand...
Replace(GetCategories__CatID, "'", "''") + ")}"
GetCategories.CursorType = 0
GetCategories.CursorLocation = 2
GetCategories.LockType = 1
GetCategories.Open()

GetCategories_numRows = 0
%>
<%
Dim GetSubCatName__CatID
GetSubCatName__CatID = "1"
If (Request.QueryString("parentcatid") <> "") Then
GetSubCatName__CatID = Request.QueryString("parentcatid")
End If
%>
<%
Dim GetSubCatName
Dim GetSubCatName_numRows

Set GetSubCatName = Server.CreateObject("ADODB.Recordset")
GetSubCatName.ActiveConnection = MM_BCH_STRING
GetSubCatName.Source = "{call dbo.GetSubCategory(" +
Click to expand...
Replace(GetSubCatName__CatID, "'", "''") + ")}"
GetSubCatName.CursorType = 0
GetSubCatName.CursorLocation = 2
GetSubCatName.LockType = 1
GetSubCatName.Open()

GetSubCatName_numRows = 0
%>
<%
Dim Repeat1__numRows
Dim Repeat1__index

Repeat1__numRows = 20
Repeat1__index = 0
GetCategories_numRows = GetCategories_numRows + Repeat1__numRows
%>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Choose a Category</title>
<link href="../styles/****.css" rel="stylesheet" type="text/css" />
</head>

<body>
<div class="contentwrap">
<h1><%=(GetSubCatName.Fields.Item("CategoryName").Value)%></h1>
<div class="content">
<table width="100%" border="0" cellspacing="2" cellpadding="4">
<%
While ((Repeat1__numRows <> 0) AND (NOT GetCategories.EOF))
%><tr>
<td><a href="listing.asp?parentcatid=<%=
Click to expand...
Request.QueryString("parentcatid")%>&catid=<%=(GetCategories.Fields.Item("ca
tID").Value)%>"> said:
</tr><%
Repeat1__index=Repeat1__index+1
Repeat1__numRows=Repeat1__numRows-1
GetCategories.MoveNext()
Wend
%>
</table>


</div>
</div>
</body>
</html>
<%
GetCategories.Close()
Set GetCategories = Nothing
%>
<%
GetSubCatName.Close()
Set GetSubCatName = Nothing
%>
</code>

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