N
Nikola Skoric
I have a very simple win32serviceutil script:
import win32serviceutil, time
win32serviceutil.StartService("burek", "localhost")
time.sleep(10)
exit()
It successfuly imports win32serviceutil, and chokes on StartService:
Traceback (most recent call last):
File "foobar.py", line 3, in ?
win32serviceutil.StartService("burek", "localhost")
File "C:\Python24\Lib\site-packages\win32\lib\win32serviceutil.py", line
399, in StartService
hs = SmartOpenService(hscm, serviceName, win32service.SERVICE_ALL_ACCESS)
File "C:\Python24\Lib\site-packages\win32\lib\win32serviceutil.py", line
76, in SmartOpenService
return win32service.OpenService(hscm, name, access)
pywintypes.error: (1060, 'OpenService', 'The specified service does not
exist as an installed service.')
What does that mean?
import win32serviceutil, time
win32serviceutil.StartService("burek", "localhost")
time.sleep(10)
exit()
It successfuly imports win32serviceutil, and chokes on StartService:
Traceback (most recent call last):
File "foobar.py", line 3, in ?
win32serviceutil.StartService("burek", "localhost")
File "C:\Python24\Lib\site-packages\win32\lib\win32serviceutil.py", line
399, in StartService
hs = SmartOpenService(hscm, serviceName, win32service.SERVICE_ALL_ACCESS)
File "C:\Python24\Lib\site-packages\win32\lib\win32serviceutil.py", line
76, in SmartOpenService
return win32service.OpenService(hscm, name, access)
pywintypes.error: (1060, 'OpenService', 'The specified service does not
exist as an installed service.')
What does that mean?