Word wrapping.

[listrecv]

Is there a simple way to use Ruby to wrap a long string to a set
interval, on whitespace?

IE - take String x, and break it up on whitespace boundaries, so that
no col is over L chars (bytes in Ruby :-( ) long?

I'm not sure if it would be better to convert spaces to newlines, or to
just add the newline after the space. (Any ideas?)

Also, newlines, tabs, multiple spaces, etc. should be preserved.

 

[phasis]

Hi,

There many threads about word wrapping
Try google on comp.lang.ruby with word wrap

http://groups.google.co.kr/group/comp.lang.ruby/search?group=comp.lang.ruby&q=word+wrap&qt_g=1

Regards,

Park Heesob

 

[listrecv]

Wow! Not bad - only 12 minutes later, and your response itself is on
the Google search page. Talk about quick indexing!

Thanks for the tip.

 

[James H.]

Naively...

1. Read the string.
2. Slice the string on spaces
words = string.split(/ /)
3. Construct a new output string
words.each {|word| output_string.concat("#{word} ") if
(output_string.length + word.length) < MAX_LENGTH
4. Print out the new line

How's that work?

James H

 

[listrecv]

In case anyone's interested:

require 'rubygems'
require_gem 'text-format'

formatter = Text::Format.new
formatter.columns = ARGV[0] || 76
formatter.first_indent = 0 # Don't tab new paragraphs

puts formatter.paragraphs(STDIN.read)

 

[ian k.]

In case anyone's interested:

require 'rubygems'
require_gem 'text-format'

formatter = Text::Format.new
formatter.columns = ARGV[0] || 76
formatter.first_indent = 0 # Don't tab new paragraphs

puts formatter.paragraphs(STDIN.read)

you could also use the unix fmt utility:
`fmt -w 72`

not sure if it's quicker.