writing 6 items in one line.

[Ronen Kfir]

Hi,
I have this code:


#include <stdio.h>
void main()
{
int i,n=40;
float a=0,b=1;
for (i=1;i<=n;i++)
{
printf("%.0f\n",a);
printf("%.0f\n",b);
a+=b;
b+=a;
}

getch();
}

It present Fibonacci serial of 40 elements. Now I need to divide it to
groups of 6 in each row.

Please help me do it.

Cheers.



 

 

[Christopher Benson-Manica]

#include <stdio.h>
void main()

^^^^
Wrong. main() returns int.

{
int i,n=40;
float a=0,b=1;

Why are these floats?

for (i=1;i<=n;i++)
{
printf("%.0f\n",a);
printf("%.0f\n",b);

printf( "%.0f %.0f", a, b );
if( i%3 == 0 )
printf( "\n" );

a+=b;
b+=a;
}

getch();
}

Printing the last newline if needed is left as an exercise.

 

[Dan Pop]

#include <stdio.h>
void main()
{
int i,n=40;
float a=0,b=1;
for (i=1;i<=n;i++)
{
printf("%.0f\n",a);
printf("%.0f\n",b);
a+=b;
b+=a;
}

getch();
}

It present Fibonacci serial of 40 elements. Now I need to divide it to
groups of 6 in each row.

Please help me do it.

No way, until you read the FAQ and modify your program accordingly.

Dan

 

[Irrwahn Grausewitz]

Hi,
I have this code:

It present Fibonacci serial of 40 elements. Now I need to divide it to
groups of 6 in each row.

Please help me do it.

- If you've already learned about the % modulus operator, think
about how it could be used to emit a newline character only
every three loop iterations.

- Otherwise, consider using an auxiliary counter variable in
the loop.

HTH
Regards

 

[Nick Keighley]

I have this code:

#include <stdio.h>
void main()

int main (void)

main() *always* returns int

{
int i,n=40;
float a=0,b=1;
for (i=1;i<=n;i++)
{
printf("%.0f\n",a);
printf("%.0f\n",b);
a+=b;
b+=a;
}

getch();

non-standard call

}

It present Fibonacci serial of 40 elements. Now I need to divide it to
groups of 6 in each row.

maintain a count of how many elements you've printed so far. When it gets
to six print a newline and reset the counter.