XSL query

[Michael O'Shea]

All, here are a few lines of contrived XSL to demonstrate my problem.


<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:test1="http://www.somewhere.com/test1"
xmlns:test2="http://www.somewhere.com/test1"
xmlns:mml="http://www.w3.org/1998/Math/MathML">
<xsl:template match="/">
<foo>
<bar>bar1</bar>
<bar>bar2</bar>
</foo>
</xsl:template>




When I transform any bit of XML with this XSL, I get the following

<?xml version="1.0"?>
<foo xmlns:test1="http://www.somewhere.com/test1"
xmlns:test2="http://www.somewhere.com/test1"
xmlns:mml="http://www.w3.org/1998/Math/MathML">
<bar>bar1</bar>
<bar>bar2</bar>
</foo>


I want

<?xml version="1.0"?>
<foo><bar>bar1</bar><bar>bar2</bar></foo>


Any suggestions to what I should be looking for in the docs would be
most welcome. The XSL is contrived - production XSL requires the
presence of the namespaces and the output produced is not static.

Regards
Mike


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[Martin Honnen]

All, here are a few lines of contrived XSL to demonstrate my problem.


<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:test1="http://www.somewhere.com/test1"
xmlns:test2="http://www.somewhere.com/test1"
xmlns:mml="http://www.w3.org/1998/Math/MathML">

Add the attribute
exlude-result-prefixes="test1 test2 mml"
to the xsl:stylesheet element to avoid those namespace declarations in
the result document
<http://www.w3.org/TR/xslt#stylesheet-element>