XSLT: getting text of a node into an attribute

[Kevin]

I have a document, lets say:

<Doc>
<Ele1 Att1='hello'>
<Ele2 Att2='goodbye'/>
</Ele1>
</Doc>

In XSLT I need to generate an attribute value which contains part of
this document as a text string, ie:

<MyOutput XML="&lt;Ele1 Att1='hello'>
&lt;Ele2 Att2='goodbye'/>
&lt;/Ele1>"/>


I can output it easily enough at child elements (copy-of), or as a
CDATA string in the element content, but I cannot find any way to get
it into an attribute.

What should I be doing?

 

[Andy Fish]

use

<xsl:attribute name="XML">
<xsl:copy-of ...> (or whatever)
</xsl:attribute>

anything you put inside here will be put into the XML attribute of the node
you're creating

 

[Kevin Burges]

Unfortunately not, I already tried that. For some reason nothing comes
through in the attribute if I do <copy-of>. I just end up with an empty
attribute.

I'm guessing copy-of outputs a nodeset rather than a string, hence you
can't stick it into an attribute value.

Any other ideas?

 

[Andy Fish]

looking at your original post, I see that I misunderstood what you meant by
'text of a node'. in XML, text is stuff that isn't inside an element or
comment. what you wanted was a textual representation of an element i.e.
with the angle brackets in.

The angle bracket notation is something that is used to serialise XML so
that it can be saved or viewed, but programs that process XML (including the
XSLT processor) don't see the angle brackets when doing the processing; they
are working with a tree of nodes. The angle brackets are only added on at
the end if you're using an output method that requires them.

So what I'm sating is that if you want to include a piece of serialized XML
in the output document you'll have to do it yourself. something like:

<xsl:template match="Doc/*">
<xsl:element name="MyOutput">
<xsl:attribute name="XML">
&lt;
<xsl:value-of select="name()"/>
<xsl:for-each select="@*">
 
<xsl:value-of select="name()"/> = &quot;<xsl:value-of
select="text()/>&quot;
&gt;
</xsl:attribute>
</xsl:element>
</xsl:template>

this is untested but I think it should give you the idea

Andy

 

[Kevin Burges]

Thanks for your help, that sounds like it will probably do the trick. I
thought I might have to do something like that, but I was hoping there
would be a way around it.