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Message: [QUOTE="James Kanze, post: 3967564"] std::string is not an aggregate, but bar is. Aggregation is determined very superficially; if the class has no user defined constructor or private data members, it is an aggregate. Something new to C++0x. It just means that the compiler should use the default implementation. In this case, I suppose that Foo is a typo for F, and it is used to say that the default constructor is the compiler generated default (and not absent, as it would be otherwise in the presence of other constructors). [/QUOTE]