Reply to thread

Message: [QUOTE="Andrey Tarasevich, post: 3524480"] By "explicit" here you probably mean "user-declared". The term "explicit" has a certain specific meaning when applied to constructors in C++, you know... Again, a problem with terminology. There's no such thing as "default copy constructor". There's the default constructor. And there's the copy constructor. Both can be ether user-declared or compiler-declared. I assume your question is about the compiler-declared copy constructor. Providing a user-declared default constructor will not really "cause" anything to happen to compiler-declared copy constructor, i.e. it will not prevent the compiler from declaring the copy constructor in situations when you don't declare it yourself. Yes. Regardless of what other assignment operators you might declare, if you don't declare the copy assignment operator, the compiler will declare one for you. [/QUOTE]