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[QUOTE="Frederick Gotham, post: 2580757"]
S S posted:

String Literals have static storage duration. Therefore, it's quite 
equivalent to:

/* Step 1: We have a static duration const array. */

static char const literal_[] = {'H','e','l','l','o',0};

/* Step 2: It's appears non-const even though we're
           not allowed to modify it. */

char (&literal)[sizeof literal_] =
        const_cast<char(&)[sizeof literal_]>(literal_);

/* Step 3: We store its address in a pointer variable. */

char const *p = literal;

C++ is broken in the respect that you can't individually initialise 
individual array elements (...well you can, but it involves a work-around 
involving placement new). Anywho, simple assignment will suffice in the 
case of POD's:

char *const p = new char[6];

p[0] = 'H';
    p[1] = 'e';
    p[2] = 'l';
    p[3] = 'l';
    p[4] = 'o';
    p[5] = 0;

delete [] p;

The behaviour of altering const data is not defined by the International 
C++ Standard. In compiling that code, any conforming compiler is entitled 
to produce a program which does absolutely anything (and yes, I mean 
_anything_).

Syntax error -- it sort of looks like a definition, except there's no name 
for the object. Anywho, if you want a non-const char array which contains a 
null-terminated string at the point of initialisation, then maybe play 
around with:

char str[] = "Hello";

Don't be fooled by the syntax -- the thing on the left is NOT a string 
literal, it's just a pretty way of writing:

char str[] = {'H','e','l','l','o',0};
[/QUOTE]

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