Hi Guru,
If I have string like "0D76" for example, it is actually a 0x0D76 in hex
"0D76" is a string. It occupies five char.
0x0D76 is not a string. It occupies at most 2 bytes.
Don't confuse the two and please try not to confuse us by introducing
completely extraneous data. You either want to process the first or
the second. I assume form actually you want to deal with the second.
format.
How can I convert the hex string 0D76 into decimal value ? So that I will
get decimal value 3446
Where is your hex value? Where do you want the result stored?
If your hex value is already in a variable of integer type, then any
member of the printf family will do the trick.
If your hex value is not already in an array of unsigned char, you
need to get it there (memcpy if in memory, fread if in a file, etc).
Once you get it there, you need to process each hex digit (also known
as a nybble) in turn and accumulate the result in an integer of some
type. Assuming CHAR_BIT is 8 on your system, a function like the
following should get you started:
int hex_to_int(unsigned char hex[], int count)
{
int sum = 0;
int i;
int temp;
for (i = 0; i < count; i++)
{
temp = (hex
& 0xf0U) >> 4;
sum = sum*16 + temp;
temp = (hex & 0xofU);
sum = sum*16 + temp;
}
return sum;
}
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