convert string with comma into an integer

[kiwi]

hi,
i need to convert a string like this 4,674 into an interger, but
couldn't figure out how to do this.
without using of Regexp.

any help will be appriciated.

 

[John Bokma]

hi,
i need to convert a string like this 4,674 into an interger, but
couldn't figure out how to do this.
without using of Regexp.

And the problem is? Doing it without a regexp? Why?

 

[kiwi]

And the problem is? Doing it without a regexp? Why?

Since i'm getting error: can't locate Regexp/Common.pm . i guess that
the machine that i'm using doesn't have this module...?

 

[Gunnar Hjalmarsson]

i need to convert a string like this 4,674 into an interger, but
couldn't figure out how to do this without using of Regexp.

(my $int = '4,674') =~ tr/,//d;

See "perldoc perlop".

 

[Jürgen Exner]

i need to convert a string like this 4,674 into an interger, but
couldn't figure out how to do this.

Insufficient information.You didn't even tell us what result you expect:
- do you want to round? This would yield 5 in your example but it would
yield 4 for e.g. 4,123
- or do you want take just the integer portion, e.g. 4 in your example and
for 4,123. Then there is still the question what you want to happen for
negative numbers, e.g. -4,674. Do you want the integer portion (-4) or the
next lower number (-5).

Anyway, "perldoc -q round" will probably get you started.

jue

 

[usenet]

Is this comma a thousands-separator (as is common in the U.S.) or a
fractional (decimal) separator (as is common in Europe)?

 

[John Bokma]

Happy Customers: http://castleamber.com/testimonials.html

Since i'm getting error: can't locate Regexp/Common.pm . i guess that
the machine that i'm using doesn't have this module...?

Install it using ppm :-D.

 

[kiwi]

Is this comma a thousands-separator (as is common in the U.S.) or a
fractional (decimal) separator (as is common in Europe)?

the thousands-separator... anyway, it works now. thanks for the help.
sorry for not giving more accurate definition.