converting some simple pseudocode to c++

Discussion in 'C++' started by Joah Senegal, Dec 17, 2007.

  1. Joah Senegal

    Joah Senegal Guest

    Hello all,

    I;m a beginner C++ and I;m trying to convert some pseudocode into C++. Its
    pseudo code of the peterson algorithm for N-processes.

    I almost converted the whole code. But the last lines are very hard.

    This is the pseudo code:

    for [ k=1 to n except k==i ]

    This is pretty simple code although I don;t know how to convert in into c++
    because of the except in the pseudocode. for [k=1 to n] to c++ is for
    (k=1;k<n;k++). i dont understand it because of the except.

    Is there anyone who can tell me what the C++ code is for the above pseudo

    I;ve another little bit more complex part of pseudocode as well

    wait until ((for all k<>i q[k]<j) or (turn[j]<>i)).

    Is there anyone who can give me the c-code for one of this pseudo codes ? I
    would be very gratefull if anyone can translate one of the pseudocodes. this
    one is the most important

    for [ k=1 to n except k==i ]

    many many thanks!!!!
    Joah Senegal, Dec 17, 2007
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  2. Joah Senegal

    Lance Diduck Guest

    for(int k=1,k!=n;++k){
    //do stuff
    Lance Diduck, Dec 17, 2007
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  3. Note that in Lance's answer the condition for the loop is k<=n, not
    k<n like you gave here.
    Since C++ does not have "wait" equivalent, you might want to give
    more context to see if the translation is possible. Of course,
    most likely, due to 'for all' a single-line translation isn't what
    you'd naturally come up with. 'for all' needs a loop. Even if
    you manage to utilise standard function like 'for_each' or some
    such, you would still most likely need a functor, which will be
    written as a separate class. For now this is what it looks like
    to me:

    // wait somehow

    bool all_q_are_less_than_j = true;
    for (int k = start_k; k <= end_k; ++k) { // start_k, end_k???
    if (k != i && !(q[k] < j)) {
    all_q_are_less_than_j = false;
    // here is your 'until'
    if (all_q_are_less_than_j || turn[j] != i)
    // do something, like move forward or whatever...
    goto wait_here;

    Victor Bazarov, Dec 17, 2007
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