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Message: [QUOTE="Bjarke Hammersholt Roune, post: 4059079"] From the draft 2 of the standard that I could find online, it says: To default-initialize an object of type T means: — if T is a non-POD class type (9), the default constructor for T is called (and the initialization is ill- formed if T has no accessible default constructor); — if T is an array type, each element is default-initialized; — otherwise, the storage for the object is zero-initialized. That got me looking for what exactly the definition of a POD is A POD-struct is an aggregate class that has no non-static data members of type pointer to member, non- POD-struct, non-POD-union (or array of such types) or reference, and has no user-defined copy assignment operator and no user-defined destructor. An aggregate is an array or a class (9) with no user-declared constructors (12.1), no private or protected non-static data members (11), no base classes (10), and no virtual functions (10.3). and then what an aggregate class is An aggregate is an array or a class (9) with no user-declared constructors (12.1), no private or protected non-static data members (11), no base classes (10), and no virtual functions (10.3). A POD-struct is an aggregate class that has no non-static data members of type pointer to member, non- POD-struct, non-POD-union (or array of such types) or reference, and has no user-defined copy assignment operator and no user-defined destructor. I didn't know that PODs cannot have user defined constructors. So combining that with the other messages in this thread, it seems that new A[10]() will zero-initialize a POD and default construct a non-POD A. Also, new A[10] will leave PODs uninitialized, but will default construct non-PODs: — If the new-initializer is omitted: — If T is a (possibly cv-qualified) non-POD class type (or array thereof), the object is default- initialized (8.5). If T is a const-qualified type, the underlying class type shall have a user-declared default constructor. — Otherwise, the object created has indeterminate value. If T is a const-qualified type, or a (possibly cv-qualified) POD class type (or array thereof) containing (directly or indirectly) a member of const-qualified type, the program is ill-formed; Thanks for the help. Cheers Bjarke Hammersholt Roune [/QUOTE]

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