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Python
dictionary/hash and '1' versus 1
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[QUOTE="Steven D'Aprano, post: 3206041"] # How to fix this broken function without modifying the source? def foo(arg): """Returns a string instead of a number.""" return "1" # oops I meant 1 _foo = foo # save a reference to original broken function foo = lambda *args, **kwargs: int(_foo(*args, **kwargs)) # and patch it And now you can use foo(arg) confident that it will always return an int like you expect. Modifications of this technique should be obvious. [/QUOTE]
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dictionary/hash and '1' versus 1
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