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Message: [QUOTE="Your Uncle, post: 2471061"] "Richard Heathfield" It doesn't do me a lick of good to snipe source, germane to what I know, which I do not understand. You had a generic swap posted, and I frankly can't quite remember what else, but in response to the what else, I wrote: /* pruefer.c */ # include "big four.h" #define MILL (.001) int fu(int, int); int main(void) {# include <stdio.h> unsigned long g, un_long_dummy, r = s = 0; int m = 3, n = 17000, mean_less_one, t; printf("taunt::continue: Y/N"); if (getchar == 'N') break; mean_less_one = (n - m) / 2; /* you wonder why Reiner einer mistrusts syntax here until you reaun_long_dummyze every time I read a unix jerk my '\''s and '/''s switch */ /* control */ for (un_long_dummy = 0; un_long_dummy < g; ++ un_long_dummy) { t = fu(m, n); if (t <= mean_less_one) ++ r; else ++ s; } printf("r is %ul while s is %ul\n", r, s); return 0; } int fu(int m, int n) { return n; } /* end .c begin .h */ /* bigfour.h */ # include <stdio.h> # include <stdlib.h> # include <math.h> # include <time.h> /* end bigfour.h */ Does this look like C? The question is meant to proceed along two lines: q1) If I approach my compiler with this, will cl.exe give me errors/warnings. q2) I conjecture that "bigfour.h" is not included in the c standard. Given that the possibly non-standard header includes ONLY standard headers, what can a person say about it? cheers, furunculus [/QUOTE]