Extract numbers from string

[eggie5]

Say I have a phone number "(555) 555-5555" and I want to extract the
numbers from it. What's the most succinct way to do this? E.g.:

old_num = "(555) 111-5555"
new_num = "5551115555"

old_num = "555-666-7777"
new_num = "5556667777"

 

[Phil Meier]

Say I have a phone number "(555) 555-5555" and I want to extract the
numbers from it. What's the most succinct way to do this? E.g.:

old_num = "(555) 111-5555"
new_num = "5551115555"

old_num = "555-666-7777"
new_num = "5556667777"

Regexp and gsub is an answer.

old_num = "(555) 111-5555"
p old_num.gsub(/[^0-9]/, '')
==> "5551115555"

old_num = "555-666-7777"
p old_num.gsub(/[^0-9]/, '')
==> "5556667777"


BR Phil

 

[Peña, Botp]

From: Nicholas Clare [mailto:[email protected]]=20
# new_num =3D old_num.scan(/\d/).join('')
lose this ^^

irb(main):003:0> old_num.scan(/\d/).join
=3D> "5551115555"

also,

irb(main):014:0> old_num.gsub(/[^\d]/,"")
=3D> "5551115555"
irb(main):015:0> old_num.tr("^0-9","")
=3D> "5551115555"
irb(main):018:0> old_num.delete("^0-9")
=3D> "5551115555"
irb(main):025:0> old_num.split(/[^\d]/).join
=3D> "5551115555"

i'd hope that ruby-doc can doc such related methods.. something like =
documenting "The Many-Ways" of ruby...

kind regards -botp

 

[David A. Black]

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Hi --

From: Nicholas Clare [mailto:[email protected]]
# new_num =3D old_num.scan(/\d/).join('')
lose this ^^

irb(main):003:0> old_num.scan(/\d/).join
=3D> "5551115555"

also,

irb(main):014:0> old_num.gsub(/[^\d]/,"")
=3D> "5551115555"

Don't forget \D:

old_num.gsub(/\D/, "")


David

--=20
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Both taught by David A. Black.
See http://www.rubypal.com for more info!
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[Peña, Botp]

From: David A. Black [mailto:[email protected]]=20

#Don't forget \D:
#
# old_num.gsub(/\D/, "")
#

arggh, why do i always forget the bigcases

anyway, fr now on if i think of reverse cases, think of \D-black

thank you and kind regards -botp

 

[Jesús Gabriel y Galán]

From: David A. Black [mailto:[email protected]]

#Don't forget \D:
#
# old_num.gsub(/\D/, "")

I always wanted try the benchmark stuff, and this seemed like a good
opportunity .

cat remove_nondigits.rb && ruby remove_nondigits.rb
# remove_nondigits.rb
# 25 September 2007
#

require 'benchmark'

n =3D 100_000
old_num =3D "(555) 55-555-55"

Benchmark.bmbm do |x|
x.report("scan") do
n.times {old_num.scan(/\d/).join}
end
x.report("gsub") do
n.times {old_num.gsub(/[^\d]/,"")}
end
x.report("gsub2") do
n.times {old_num.gsub(/\D/, "")}
end
x.report("tr") do
n.times {old_num.tr("^0-9","")}
end
x.report("delete") do
n.times {old_num.delete("^0-9")}
end
x.report("split") do
n.times {old_num.split(/[^\d]/).join}
end
end
Rehearsal ------------------------------------------
scan 1.080000 0.000000 1.080000 ( 1.144654)
gsub 0.380000 0.010000 0.390000 ( 0.403057)
gsub2 0.390000 0.010000 0.400000 ( 0.416074)
tr 0.290000 0.020000 0.310000 ( 0.320764)
delete 0.270000 0.010000 0.280000 ( 0.294078)
split 0.700000 0.000000 0.700000 ( 0.714139)
--------------------------------- total: 3.160000sec

user system total real
scan 1.080000 0.020000 1.100000 ( 1.101550)
gsub 0.380000 0.010000 0.390000 ( 0.404968)
gsub2 0.380000 0.010000 0.390000 ( 0.409364)
tr 0.290000 0.020000 0.310000 ( 0.318723)
delete 0.280000 0.010000 0.290000 ( 0.294650)
split 0.700000 0.000000 0.700000 ( 0.713261)

So it seems that in terms of speed, delete wins, second place for tr,
and in the fight between [^\d] and \D the first one wins by a little
(very little) margin .

Cheers,

Jesus.

 

[Peña, Botp]

From: Jes=FAs Gabriel y Gal=E1n [mailto:[email protected]]=20
# I always wanted try the benchmark stuff, and this seemed
# like a good opportunity .

wow. thanks for the bnchmark, Jesus.

kind regards -botp

 

[eggie5]

From: David A. Black [mailto:[email protected]]

#Don't forget \D:
#
# old_num.gsub(/\D/, "")

I always wanted try the benchmark stuff, and this seemed like a good
opportunity .

cat remove_nondigits.rb && ruby remove_nondigits.rb
# remove_nondigits.rb
# 25 September 2007
#

require 'benchmark'

n = 100_000
old_num = "(555) 55-555-55"

Benchmark.bmbm do |x|
x.report("scan") do
n.times {old_num.scan(/\d/).join}
end
x.report("gsub") do
n.times {old_num.gsub(/[^\d]/,"")}
end
x.report("gsub2") do
n.times {old_num.gsub(/\D/, "")}
end
x.report("tr") do
n.times {old_num.tr("^0-9","")}
end
x.report("delete") do
n.times {old_num.delete("^0-9")}
end
x.report("split") do
n.times {old_num.split(/[^\d]/).join}
end
end
Rehearsal ------------------------------------------
scan 1.080000 0.000000 1.080000 ( 1.144654)
gsub 0.380000 0.010000 0.390000 ( 0.403057)
gsub2 0.390000 0.010000 0.400000 ( 0.416074)
tr 0.290000 0.020000 0.310000 ( 0.320764)
delete 0.270000 0.010000 0.280000 ( 0.294078)
split 0.700000 0.000000 0.700000 ( 0.714139)
--------------------------------- total: 3.160000sec

user system total real
scan 1.080000 0.020000 1.100000 ( 1.101550)
gsub 0.380000 0.010000 0.390000 ( 0.404968)
gsub2 0.380000 0.010000 0.390000 ( 0.409364)
tr 0.290000 0.020000 0.310000 ( 0.318723)
delete 0.280000 0.010000 0.290000 ( 0.294650)
split 0.700000 0.000000 0.700000 ( 0.713261)

So it seems that in terms of speed, delete wins, second place for tr,
and in the fight between [^\d] and \D the first one wins by a little
(very little) margin .

Cheers,

Jesus.

That's awesome, thanks.