Reply to thread

Message

[QUOTE="Mike Kazantsev, post: 3870924"]
You can use iterators to efficiently parse no-matter-how-large file.
Following code depends on line breaks and 'end' statement rather than
indentation.

import itertools as it, operator as op, functools as ft
  from string import whitespace as spaces

with open('test.src') as src:
    lines = it.ifilter(bool, it.imap(lambda x: x.strip(spaces), src))
    sections = ( (lines.next(), dict(it.imap(str.split, lines))) for sep,lines in
      it.groupby(lines, key=lambda x: x == 'end') if not sep )
    data = dict(sections)

print data
  # { 'parameters2': {'key2': 'value2', 'key1': 'value1'},
  #  'parameters1': {'key2': 'value2', 'key1': 'value1'} }

To save namespace and make it a bit more unreadable you can write it
as a one-liner:

with open('test.src') as src:
    data = dict( (lines.next(), dict(it.imap(str.split, lines))) for sep,lines in
      it.groupby(it.ifilter(bool, it.imap(lambda x: x.strip(spaces), src)),
      key=lambda x: x == 'end') if not sep )

-- 
Mike Kazantsev // fraggod.net

-----BEGIN PGP SIGNATURE-----
Version: GnuPG v2.0.11 (GNU/Linux)

iEYEARECAAYFAkogabEACgkQASbOZpzyXnFOcwCgkxnm6pBNywpwWSeUs2md8dQA
F4oAoPBNqAjf2gcgnCE48rscD0BbeFDV
=rsy6
-----END PGP SIGNATURE-----
[/QUOTE]

Verification