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Message: [QUOTE="Larry Bates, post: 1779733"] Paul has explanation (see his response), but I wanted to expand a little. def foo(*args, **kwargs): for arg in args: print arg for key, value in kwargs.items(): print key, value return a b y 2 x 1 or def foo(list_of_args, **kwargs): # # Now call function with args as individual arguments # and keyword arguments as individual keyword # arguments also. # call_other_function(*list_of_args, **kwargs) return Hope this helps, Larry Bates [/QUOTE]