function nested

[Gigs_]

i have this function.

def f(start):
stack = []
def f1(start):
for fname in os.listdir(startDir):
path = os.path.join(startDir, fname)
if os.path.isfile(path):
stack.append(path)
else:
f1(path)
return stack


this is returning empty list, why?


thanks

 

[Peter Otten]

i have this function.

def f(start):
stack = []
def f1(start):
for fname in os.listdir(startDir):
path = os.path.join(startDir, fname)
if os.path.isfile(path):
stack.append(path)
else:
f1(path)
return stack


this is returning empty list, why?

Because f() doesn't invoke f1().

Peter

 

[Bruno Desthuilliers]

Gigs_ a écrit :

i have this function.

def f(start):
stack = []
def f1(start):
for fname in os.listdir(startDir):
path = os.path.join(startDir, fname)
if os.path.isfile(path):
stack.append(path)
else:
f1(path)
return stack


this is returning empty list, why?

Because that's what you are returning. Perhaps did you mean to actually
*call* f1() after defining it ?-)