Help - Exercise Decision

[kennedysalvino.ks]

I'm trying to make a ranking of 3 numbers and say which the greatest and consider whether there is a tie between them, I am not able to make the conditions of draws.

Code in PT-BR: http://pastebin.com/18pYJjPC

 

[Gary Herron]

I'm trying to make a ranking of 3 numbers and say which the greatest and consider whether there is a tie between them, I am not able to make the conditions of draws.

Code in PT-BR: http://pastebin.com/18pYJjPC

Please post the code directly in this message. As a matter of
safe-browsing practices, I won't follow that link.

One tests for equality (draws as you call them) with the == operator.
In what way does that not work for you? Your question is so terse, that
I'm not sure what you want. Provide some examples please.

Gary Herron

 

[Kennedy Salvino]

Em domingo, 10 de novembro de 2013 21h34min39s UTC-3, Gary Herron escreveu:

Please post the code directly in this message. As a matter of

safe-browsing practices, I won't follow that link.



One tests for equality (draws as you call them) with the == operator.

In what way does that not work for you? Your question is so terse, that

I'm not sure what you want. Provide some examples please.



Gary Herron

Using only if elif else, here is the code

primeira_pontuacao = int(input("Digite a primeira pontuação: "))
segunda_pontuacao = int(input("Digite a segunda pontuação: "))
terceira_pontuacao = int(input("Digite a terceira pontuação: "))
'''
empate = primeira_pontuacao == segunda_pontuacao or terceira_pontuacao
empate2 = segunda_pontuacao == primeira_pontuacao or terceira_pontuacao
empate3 = terceira_pontuacao == primeira_pontuacao or segunda_pontuacao
empate4 = primeira_pontuacao == terceira_pontuacao != segunda_pontuacao
empate5 = segunda_pontuacao == terceira_pontuacao != primeira_pontuacao
empate6 = terceira_pontuacao == segunda_pontuacao != primeira_pontuacao
empate7 = primeira_pontuacao == segunda_pontuacao == terceira_pontuacao
'''
colocacao1 = 0
colocacao2 = 0
colocacao3 = 0

if (primeira_pontuacao > segunda_pontuacao):
if(segunda_pontuacao > terceira_pontuacao):
colocacao1 = primeira_pontuacao
colocacao2 = segunda_pontuacao
colocacao3 = terceira_pontuacao
else:
colocacao1 = primeira_pontuacao
colocacao2 = terceira_pontuacao
colocacao3 = segunda_pontuacao
elif (segunda_pontuacao > terceira_pontuacao):
if(terceira_pontuacao > primeira_pontuacao):
colocacao1 = segunda_pontuacao
colocacao2 = terceira_pontuacao
colocacao3 = primeira_pontuacao
else:
colocacao1 = segunda_pontuacao
colocacao2 = primeira_pontuacao
colocacao3 = terceira_pontuacao
elif (terceira_pontuacao > segunda_pontuacao):
if(segunda_pontuacao > primeira_pontuacao):
colocacao1 = terceira_pontuacao
colocacao2 = segunda_pontuacao
colocacao3 = primeira_pontuacao
else:
colocacao1 = terceira_pontuacao
colocacao2 = primeira_pontuacao
colocacao3 = segunda_pontuacao
elif (primeira_pontuacao > terceira_pontuacao):
if(terceira_pontuacao > segunda_pontuacao):
colocacao1 = primeira_pontuacao
colocacao2 = terceira_pontuacao
colocacao3 = segunda_pontuacao
else:
colocacao1 = primeira_pontuacao
colocacao2 = segunda_pontuacao
colocacao3 = terceira_pontuacao
elif (segunda_pontuacao > primeira_pontuacao):
if (primeira_pontuacao > terceira_pontuacao):
colocacao1 = segunda_pontuacao
colocacao2 = primeira_pontuacao
colocacao3 = terceira_pontuacao
else:
colocacao2 = segunda_pontuacao
colocacao3 = terceira_pontuacao
colocacao1 = primeira_pontuacao
elif (terceira_pontuacao > primeira_pontuacao):
if(primeira_pontuacao > segunda_pontuacao):
colocacao1 = terceira_pontuacao
colocacao2 = primeira_pontuacao
colocacao3 = segunda_pontuacao
else:
colocacao1 = terceira_pontuacao
colocacao2 = segunda_pontuacao
colocacao3 = primeira_pontuacao

print("O primeiro: " , colocacao1)
print("O segundo: ", colocacao2)
print("O terceiro: ", colocacao3)

 

[Gary Herron]

Em domingo, 10 de novembro de 2013 21h34min39s UTC-3, Gary Herron escreveu:

Using only if elif else, here is the code

Holy HELL man, that's a lot of code for such a simple problem. But
perhaps your assignment requires you to do it this way. (In which case
I'd have a word with your teacher.)

But assuming you've got the sorting part correct, (which you don't quite
-- the three numbers 2 1 3 entered in that order don't sort correctly),
I'll guess the problem is in the 8 lines you have triple-quoted out, true?

The first of those lines won't do what I think you are trying to do. Try
this instead (I'm using a, b, and c instead of your variables):
empate = a==b or a==c
Each == test produces a True/False value and the "or" combines the two
into a single True/False. Your code
empata = a == b or c
does something much different.

That being said, I have to question what you are going to do with 8 such
computations. A single test like
if a==b or b==c or a==c:
would tell you if any two of the three values are equal. Do you need
more information than that?

And then I feel compelled to add one more comment: Your method of
sorting three numbers is extremely wordy and inefficient. What part of
that did you invent, and what part is forced on you by your teacher? Are
you allowed to be “smarter” about it, and would you like some advice on
that part?

Gary Herron

 

[Mark Lawrence]

Holy HELL man, that's a lot of code for such a simple problem. But
perhaps your assignment requires you to do it this way. (In which case
I'd have a word with your teacher.)

But assuming you've got the sorting part correct, (which you don't quite
-- the three numbers 2 1 3 entered in that order don't sort correctly),
I'll guess the problem is in the 8 lines you have triple-quoted out, true?

The first of those lines won't do what I think you are trying to do. Try
this instead (I'm using a, b, and c instead of your variables):
empate = a==b or a==c
Each == test produces a True/False value and the "or" combines the two
into a single True/False. Your code
empata = a == b or c
does something much different.

That being said, I have to question what you are going to do with 8 such
computations. A single test like
if a==b or b==c or a==c:
would tell you if any two of the three values are equal. Do you need
more information than that?

And then I feel compelled to add one more comment: Your method of
sorting three numbers is extremely wordy and inefficient. What part of
that did you invent, and what part is forced on you by your teacher? Are
you allowed to be “smarter” about it, and would you like some advice on
that part?

Gary Herron

Regardless of the way the OP goes about it the use of print functions or
a debugger wouldn't go amiss.

 

[Kennedy Salvino]

Em domingo, 10 de novembro de 2013 19h56min45s UTC-3, Kennedy Salvino escreveu:

I'm trying to make a ranking of 3 numbers and say which the greatest and consider whether there is a tie between them, I am not able to make the conditions of draws.



Code in PT-BR: http://pastebin.com/18pYJjPC

My teacher asked .. I will try to do as you said.

 

[Kennedy Salvino]

My teacher asked .. I will try to do as you said.