Help. Using a variable to get the position of a node.

[Donal]

I have the following:

<xsl:variable name="position"><xsl:value-of
select="position"/></xsl:variable>
<xsl:attribute name='style'><xsl:value-of
select="//ExportData/Definition/Column[$position]/Style"/></xsl:attribute>

However, //ExportData/Definition/Column[$position]/Style always seem to return //ExportData/Definition/Column[1]/Style.

Any ideas?

 

[Dimitre Novatchev]

"Donal" wrote:

I have the following:

<xsl:variable name="position"><xsl:value-of
select="position"/></xsl:variable>
<xsl:attribute name='style'><xsl:value-of
select="//ExportData/Definition/Column[$position]/Style"/></xsl:attribute>

However, //ExportData/Definition/Column[$position]/Style always seem to return //ExportData/Definition/Column[1]/Style.

Any ideas?

Use:

<xsl:variable name="position" select="position"/>

Outputting a value (as you did) in the body of an xsl:variable makes it contain an RTF (Result Tree Fragment), which has a root with a single text node child. A tree used in a predicate is evaluated as a boolean and always returns true. This means that:

//ExportData/Definition/Column[$position]/Style

selects all "Style" children of all //ExportData/Definition/Column elements (because the predicate is true and does not eliminate any node.

Then, given a nodeset, xsl:value-of outputs the first node in document order. This is how you got the first "Style" child of:

//ExportData/Definition/Column[1]

=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

 

[Donal Conlon]

Excellent explanation, thank you.

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