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C++
How do you round off a float?
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[QUOTE="Mike Hewson, post: 1524841"] Integer casts will truncate to the right of the decimal point. This suggests moving the point back and forth. *pseudocode* declare somenumber; // 3.1415 declare someprecision; // x, say equals 1. shifter = 10_to_the_power_of( someprecision ); shift_it = somenumber*shifter; truncate_it = integer_part_of( shift_it ); shift_it_back = truncate_it/shifter; // Result. *end pseudocode* [/QUOTE]
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How do you round off a float?
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