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Message: [QUOTE="MegaC, post: 4762807"] Hi all, I am trying to create a installation script for our product at work. The script involves prompting the user for the pathname of Apache (and other components not mentioned here). I then plan to take this user-entered pathname and edit the http.conf file, by globally replacing all occurances of a place holder called "APACHE_HOME" with a ms-dos variable containing the install path entitled %APACHE_HOME%. So, in my ms-dos script, I have something like this: ..... set APACHE_HOME=%userManualPathofApache% .... set PERL_EXE=%IPLANET_HOME/bin/shared/library/perl @rem Above line is the path to the perl version used by iPlanet .... %PERL_EXE% -wpe s/APACHE_HOME/"%APACHE_HOME%"/ < httpd.conf > httpd.conf.mod move /Y httpd.conf.mod httpd.conf What I want to happen is for the ms-dos script to call perl to globally replace all occurances of the placeholder APACHE_HOME with the interpolated variable of %APACHE_HOME% which contains the install path of Apache (eg. C:/Program Files/Apache/Apache2). However, because of the backslashes in the directory name, the substution strips out the /s and leaves C:Program FilesApacheApache2. I tried changing the delimiter from a / to a #, by this command: %PERL_EXE% -wpe s#APACHE_HOME#"%APACHE_HOME%"# < httpd.conf > httpd.conf.mod but I still get the resulting substitution of : C:Program FilesApacheApache2 I know what your thinking, just get the user to enter C://Program Files//Apache//Apache2 ... well I tried that and it STILL gives me the same result of C:Program FilesApacheApache2 in the httpd.conf file. Help!! How do I take the user input of 'C:/Program Files/Apache/Apache2' and use the command of %PERL_EXE% -wpe s#APACHE_HOME#"%APACHE_HOME%"# < httpd.conf > httpd.conf.mod to substitute every occurance of APACHE_HOME with C:/Program Files/Apache/Apache2 as intended? Please help! I am so frustrated by this and it seems like it must be so easy to do!! Please respond to com.rogers@dmegyesi (for SPAM) Thanks, Derek [/QUOTE]

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