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Message: [QUOTE="Army1987, post: 2961580"] I guess you have 32-bit ints with 2's complement. The C99 rationale (6.4.4.4.)says "Notwithstanding the general rule that literal constants are non-negative, 3..." where the footnote is "3 Note that -4 is an expression: unary minus with operand 4.". INT_MAX is 0x7FFFFFFF, so a decimal constant of 0x80000000 doesn't fit in a signed int, and if INT_MAX == LONG_MAX, not even in a signed long. In C89 this would cause it to have unsigned type. Negating it yields UINT_MAX + 1 - 0x80000000 which is 0x80000000, which doesn't fit in a signed int. Try using: long a = -2147483647 - 1, for example MSVC #define's INT_MIN this way (but with parentheses around it). Note that in C89 no type is *required* to be able to hold that value, so the program won't be portable everywhere. But using long will make it portable even on systems with 16-bit int, provided they use two's complement. (Or INT_MIN if you mean that. If you have C99 maybe you want to use INT32_MIN and declare a as an int32_t, these are defined in <stdint.h>.) [/QUOTE]