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Message: [QUOTE="Paolo Pantaleo, post: 2039974"] Hi this exaple: def lcl(): n=1 x=locals() x["n"]=100 print "n in lcl() is:" +str(n) #This will say Name error #x["new"]=1 #print new n=1 x=globals() x["n"]=100 print "gobal n is:" +str(n) x["new"]=1 print "new is:" +str(new) lcl() produces gobal n is:100 new is:1 n in lcl() is:1 shouldn't be n in lcl() 100 too? why accessing the names dictionary globals() and locals() gives different results? This example was made using Python 2.4.3 (#69, Mar 29 2006, 17:35:34) [MSC v.1310 32 bit (Intel)] on win32 PAolo [/QUOTE]