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Message: [QUOTE="Vikrant Singh, post: 4597630"] Hello All, This is the first time I am working on Ruby and I am not sure if I am asking very basics of the language. I am working on a tool which is written in Ruby and I need to implement a new feature in it. Although itâ€™s a small update still to work and understand the code I need to learn the basics of Ruby first. I am using â€œProgramming Ruby, 2nd Editionâ€ by Dave Thomas as a reference. Its a good book and I am able to proceed using it. Today I got stuck in memory handling code Following is what I am doing and need your comments on the sameâ€¦ 1.Working in a function which receives number of bytes as argument. 2.I need to allocate memory (double in the size sent in argument) to a buffer and also initialize all the bits to zero. I wrote following code for the last two pointsâ€¦ def FunctionName (numBytes) bufferSize = numBytes*2 buffer = dl.malloc(bufferSize) end I am using this dl.malloc after taking reference from existing code. Here I searched in the book and found that Ruby presents its own APIs for memory allocation. I also found that dl is a way of using win32 APIs instead of Rubyâ€™s API. Which one is better? Also, after allocation how to make sure that memory is initialized with all zeros. 3.Set the 10th bit in the buffer buffer[bufferSize -2] = buffer[bufferSize -2] | 0x4 4.Execute some library calls with this buffer 5.Clear the buffer again I searched the book and found that clear function is used to clear the content of an array. I am not sure if the same will work with the dynamically allocated buffer as well. Buffer.clear 6.Execute some library calls again in this buffer 7.Copy the first half of the buffer in a new buffer and second half of the buffer in another. firstHalf = dl.malloc(numBytes) secondHalf = dl.malloc(numBytes) #Copy numBytesâ€¦numBytes/2 memcpy(firstHalf, buffer, numBytes) #Copy numbytes/2 â€¦ 0 Memcpy(secondHalf, buffer[0..numBytes/2], numbytes) Please reply with your view on the same. Please correct me if I am wrong somewhere. [/QUOTE]

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