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Message: [QUOTE="James Tucker, post: 4597639"] def FunctionName(numBytes) bufferSize =3D numBytes * 2 buffer =3D "\0" * bufferSize end Most of the external interfaces can use strings as sets of binary =20 data, as this is our best binary representation at present. If you use a ruby string, instead of a dl.malloc, the only thing you =20 need to ensure is that the data is not GC'd prematurely. This will =20 happen if there are no references left on the ruby side. I can't comment on the semantics of dl, as I've never used it. first_half =3D buffer[0..half] sec_half =3D buffer[half..-1] You won't need to memcpy if you're treating the data as a regular ruby =20= string. [/QUOTE]