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C++
no-fail swap for char []'s
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[QUOTE="Dennis Jones, post: 3407292"] A couple of changes got it to work: template<unsigned s> void strswap(char (a1)[s], char (a2)[s]) // removed the '&'s { for (unsigned i = s; i-- > 0; ) std::swap(a1[i], a2[i]); } class Test { public: char str[10]; void swap( Test &rhs ) { strswap<10>( str, rhs.str ); // added the "<10>" } }; So, apparently, the compiler *cannot* deduce 's' at compile-time (or I'm still doing something wrong). - Dennis[/i][/i][/s][/s] [/QUOTE]
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no-fail swap for char []'s
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