printf question

[Scot]

Having trouble figuring out how to do this:

Have a number, say 15109.

How do I use printf to make it 15.109? And then 15.1 (I think this can be
done with a %f printf)?

Thanks,

Scott

 

[Tony Curtis]

Having trouble figuring out how to do this: Have a number,
say 15109.

How do I use printf to make it 15.109? And then 15.1 (I
think this can be done with a %f printf)?

Do you mean: as in some European locales where "." is used to
separate digits in large numbers like "," does in English?

Or do you want to perform arithmetic operations (division) on
the value, then output the value to a certain precision?

hth
t

 

[Scot]

Hi Tony,

it will be representing the decimal in and English number. so i want to
move it over a certain number of spaces to the left, in this example, it
would move two spaces to the left...then have everything but one number to
the right chopped off.

Thanks,

Scott

 

[Simon Andrews]

Hi Tony,

it will be representing the decimal in and English number.
so i want to move it over a certain number of spaces to the
left, in this example, it would move two spaces to the
left...then have everything but one number to the right
chopped off.

perl -e "printf('%.1f',(1509/100))"
15.1

Adjust to taste..

HTH

Simon.

 

[Scot]

Thanks Simon. I just came across an idea from someone that i might use that
is similar where i will use length() to adjust the number of 0's that i use
in the division.

Thanks,

Scott