Reply to thread

Message: [QUOTE="Michael Ulm, post: 4525841"] --snip-- Actually, it is possible to show that for any three digit number g(x) < x. This holds in any base. The proof: Let the base be b > 1, and the number x be x = u + b * v + b^2 * w, with 0 <= u, v, w < b, and w > 0. Then x - g(x) = u + b * v + b^2 * w - (u^2 + v^2 + w^2) = u (1 - u) + v * (b - v) + w * (b^2 - w) Regards, Michael -- Michael Ulm R&D Team ISIS Information Systems Austria tel: +43 2236 27551-219, fax: +43 2236 21081 e-mail: [email]michael.ulm@isis-papyrus.com[/email] Visit our Website: [URL="http://www.isis-papyrus.com"]www.isis-papyrus.com[/URL] [/QUOTE]