Regexp: modify $1 within the replace clause?

[Yaroslav]

Hi all,

Consider the following trivial example:

$_ =~ s/<matching_expression>/<clause_that_uses_$1>/g;

Is there a way to build such a regular expression, that matches some
string and modifies the match (e.g. $1) before using it in the replace
clause? What if I want to do something with $1 before I use it to
replace something? Is there a way to insert, say, a function of $1
there, rather than $1 itself?

TIA.

~yaroslav

 

[Joe Smith]

$_ =~ s/<matching_expression>/<clause_that_uses_$1>/g;
Is there a way to insert, say, a function of $1
there, rather than $1 itself?

Read the docs, looking for e and ee modifiers.
s/(.*)/foo($1)/eeg;
-Joe

 

[nobull]

Read the docs, looking for e and ee modifiers.
s/(.*)/foo($1)/eeg;

Yes, do read the docs. The OP wants /e not /ee

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