A
Adam Risser
Hi everyone,
I am modifying the suckerfish dropdown code to use settimeout to have
a slight pause before the menus disappear to make it more user
friendly. I have hit a snag with the following statement:
li.onmouseout=function()
{
timerID=setTimeout('this.getElementsByTagName("UL")
[0].style.display = "none"', timecount);
}
If I put take the statement
this.getElementsByTagName("UL")[0].style.display = "none";
out of the settimeout function, it works. (w/o the pause, obviously).
With the settimeout function, I get "this.getElementByTagName is not a
function" error.
I have tried putting this.getElementsByTagName("UL")[0] is a variable
and then using that in the settimeout function, but then each li will
only open the very last menu in the list. (ie all the menu items open
the last sub menu)
Here is a link to a stripped down version of the code.
http://mustang.millersville.edu/~hr/index3.php
Thanks everyone!
I am modifying the suckerfish dropdown code to use settimeout to have
a slight pause before the menus disappear to make it more user
friendly. I have hit a snag with the following statement:
li.onmouseout=function()
{
timerID=setTimeout('this.getElementsByTagName("UL")
[0].style.display = "none"', timecount);
}
If I put take the statement
this.getElementsByTagName("UL")[0].style.display = "none";
out of the settimeout function, it works. (w/o the pause, obviously).
With the settimeout function, I get "this.getElementByTagName is not a
function" error.
I have tried putting this.getElementsByTagName("UL")[0] is a variable
and then using that in the settimeout function, but then each li will
only open the very last menu in the list. (ie all the menu items open
the last sub menu)
Here is a link to a stripped down version of the code.
http://mustang.millersville.edu/~hr/index3.php
Thanks everyone!