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Message: [QUOTE="djc, post: 5058396"] I learn lots of useful things from the list, some not always welcome. No sooner had I found a solution to a minor inconvenience in my code, than a recent thread here drew my attention to the fact that it will not work for python 3. So suggestions please: TODO 2012-10-22: sort order numbers first then alphanumeric('a', 'ab', 'acd', 'bcd', '1a', 'a1', '222 bb', 'b a 4') ['1', '10', '101', '13', '1a', '2', '2000', '222 bb', '3', '31', '40', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd'] Possibly there is a better way but for Python 2.7 this gives the required result Python 2.7.3 (default, Sep 26 2012, 21:51:14) [1, 2, 3, 10, 13, 31, 40, 101, 2000, '1a', '222 bb', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd'] [str(x) for x in sorted(int(x) if x.isdigit() else x for x in n+s)] ['1', '2', '3', '10', '13', '31', '40', '101', '2000', '1a', '222 bb', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd'] But not for Python 3 Python 3.2.3 (default, Oct 19 2012, 19:53:16) ['1', '10', '101', '13', '1a', '2', '2000', '222 bb', '3', '31', '40', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd'] Traceback (most recent call last): The best I can think of is to split the input sequence into two lists, sort each and then join them. [/QUOTE]