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Python
sort order for strings of digits
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[QUOTE="Ian Kelly, post: 5058399"] In the example you have given they already seem to be split, so you could just do: sorted(n, key=int) + sorted(s) If that's not really the case, then you could construct (str, int) tuples as sort keys: sorted(n+s, key=lambda x: ('', int(x)) if x.isdigit() else (x, -1)) Note that the empty string sorts before all numbers here, which may or may not be desirable. [/QUOTE]
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