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Python
sort order for strings of digits
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[QUOTE="Arnaud Delobelle, post: 5058505"] You don't actually need to split the string, it's enough to return a pair consisting of the number of leading digits followed by the string as the key. Here's an implementation using takewhile: .... return sum(1 for c in takewhile(str.isdigit, s)) or 1000, s .... ['1', '1a', '9', '55', '55a', '1000', 'abc', 'abc2'] Here's why it works: [(1, '9'), (4, '1000'), (1000, 'abc2'), (2, '55'), (1, '1'), (1000, 'abc'), (2, '55a'), (1, '1a')] [/QUOTE]
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