struct.pack returns nothing

[andmarti]

If I build a strict with:

import struct
print struck.pack ('i', 1)

it returns a '\n'.
What's wrong with it???

 

[Alex Martelli]

If I build a strict with:

import struct
print struck.pack ('i', 1)

it returns a '\n'.
What's wrong with it???

You're trying to print a binary string that's hardly printable as-is.
Try printing its repr(...) and you'll see all the binary zeros and one
you crave!-)


Alex

 

[AWasilenko]

If I build a strict with:

import struct
print struck.pack ('i', 1)

it returns a '\n'.
What's wrong with it???

Looks like you spelled struct wrong in the code

 

[andmarti]

Looks like you spelled struct wrong in the code

You're right. I meant struct there too. heh.

 

[andmarti]

You're trying to print a binary string that's hardly printable as-is.
Try printing its repr(...) and you'll see all the binary zeros and one
you crave!-)

Im getting nothing as well.
The unpack seems to work fine though.

 

[Gabriel Genellina]

Im getting nothing as well.
The unpack seems to work fine though.

Works fine for me:

py> import struct
py> print repr(struct.pack('i',1))
'\x01\x00\x00\x00'