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Message: [QUOTE="Nicolay Korslund, post: 1462439"] Hi! I'm having a little trouble with the typecast operator, can anybody help me with the rules for when the this operator is invoked? In the class 'Test' in the code below, the typecast operator returns a 'mytype'. In main() I use the [] operator on 'Test'-class objects. If 'mytype' is a pointer the [] operator works fine. But if I instead try to call an overloaded [] operator, the typecast operator is not invoked, and I get a compiler error (unless I make an explicit cast.) So does the 'operator mytype ()' only work properly with simple types? Any help would be appreciated! Nico template <class mytype> class Test { mytype i; public: operator mytype () {return i;} }; class Test2 { public: int operator [] (int i) {return i;} }; int main(void) { Test<double*> t1; Test<Test2> t2; t1[0]; // This line works fine t2[0]; // This line doesn't compile ((Test2)t2)[0]; // This also works return 0; } [/QUOTE]