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[QUOTE="flebber, post: 4393311"]
[i]

Thank You Jean-Christophe, I like the way you use the define as I
think it makes it clear and readable.

James thanks for explaining that. I had the feeling I was doing it
wrong but wasn't quite sure where it was going wrong.

So this declares my array as a global value. I can then assign a
value(size of array) to it locally. This would then mean that if I had
5 different functions they could all have their own size declared of
array a[] locally? May not be the best idea but I could do this?

With this skeleton shouldn't I declare int a[1000], ?
[i][i]

Working on it... not close yet but will get there, having issues with
local variables.

#include <stdio.h>
#define limit 1000;

int two_pointer_args(int, int); /* function using two ints */
int main()

{
two_pointer_args(int i, int j);
i, j = 0;
int i_total=0;
int j_total=0;
{
while (i < limit)
{
if ((i % 3 == 0)|| (i % 5 == 0))
{
i_total+=i;
}
else
{
j_total = i + j;
}
i++;
}
printf(" The sum of i was %d and the sum of j was %d\n", i_total,
j_total);
}
return 0;
}

Thanks for all the help Sayth.[/i][/i][/i]
[/QUOTE]

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