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[QUOTE="Marcelo De Brito, post: 3858302"]
Hi!

I have read that only the local version (overriden) of a virtual
function is available to be called inside a constructor of a class
that inherits from another (base) class (which owns the "base" virtual
function overriden by the derived one).

But the code I have written compiles fairly. See it:

#include <iostream>
using namespace std;

class b1 {
  public:
    b1() { cout << "b1::b1()" << endl; }
    virtual void f() { cout << "b1::f()" << endl; }
};

class d1 : public b1 {
  public:
    d1() : b1() {
      cout << "d1::d1()" << endl;
      b1::f();  //Calls the base class "f()" function. Shouldn't it
generate an error?
      f();        //Calls the local class "d1::f()" function
      }
    void f() {cout << "d1::f()" << endl;}
};

int main()
{
    d1 objd1;
}

I got the following return:

b1::b1()
d1::d1()
b1::f()
d1::f()

I thought the base class "b1::f()" function would be unavailable for
calling inside the derived class' constructor and only the local
version "d1::f()" could be called.

I appreciate your comments, suggestions, etc.

Thank You!

Marcelo
[/QUOTE]

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