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[QUOTE="BobR, post: 2989421"]
The one above is the only constructor (once you declare/define one, the
compiler does not). It seconds as the default constructor (can be called
with no args).

Declaration of function 'rect8' which takes no parameters, and returns an
'Rect'.
You meant:
   Rect rect8;  // default construct, like below (rect2)

Same with built-in types:
  int number();
  number = 43;
// error: assignment of function `int number()'
// error: cannot convert `int' to `int ()()' in assignment

int number2( 34 );  // or: int number2;
  number2 = 43; // ok

Remember it's an POD, the compiler supplied copy-ctor is fine.
And destructor, assignment operator. As soon as you define one of the three,
you should supply all three.

Same answer as above.

"summed up", the answer is "no".

You seem reluctant to believe that POD struct/class have the guts supplied.
Try this:

#include <iostream>

struct Bint{ int x; };  // don't come much 'plainer'

int main(){
   Bint bint1; // default construct
   bint1.x = 3;
   Bint bint2;
   bint2 = bint1; // assignment
   Bint bint3( bint1 ); // copy-ctor
   std::cout<<"bint1.x="<<bint1.x<<'\n';
   std::cout<<"bint2.x="<<bint2.x<<'\n';
   std::cout<<"bint3.x="<<bint3.x<<'\n';
   return 0;
   }
/* -out-
bint1.x=3
bint2.x=3
bint3.x=3
*/
[/QUOTE]

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