why the memcpy() is like there in glibc

[error.right]

i see the implement of memcpy() is like this in glibc 2.9
void *
memcpy (dstpp, srcpp, len)
void *dstpp;
const void *srcpp;
size_t len;
{
unsigned long int dstp = (long int) dstpp;
unsigned long int srcp = (long int) srcpp;

but why there is not unsigned long int dstp = (unsigned long int
dstp);

 

[Noob]

the [implementation] of memcpy() is like this in glibc 2.9

You should post to the libc-help mailing list.

libc-help: The libc-help list is intended for all glibc questions including
build problems, C library usage, and more. No question about glibc is ever wrong
on this list.

http://sourceware.org/glibc/
http://sourceware.org/ml/libc-help/

Regards.

 

[error.right]

the [implementation] of memcpy() is like this in glibc 2.9

You should post to the libc-help mailing list.

libc-help: The libc-help list is intended for all glibc questions including
build problems, C library usage, and more. No question about glibc is ever wrong
on this list.

http://sourceware.org/glibc/http://sourceware.org/ml/libc-help/

Regards.

thanks