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Message: [QUOTE="Andy Dingley, post: 773414"] Try this: Notes: - I'm ingnoring some whitespace issues that are rarely significant. You'd need to supply a better spec before going there. - I guess the text of the second link in your example was a typo. - This is an impossible problem to solve, as a general case from one example. I can make it work (quite easily) for that one case, but a couple of examples don't _define_ a mapping (I had to guess at this, and it's a 50:50 guess between whether to map <item> or <par class="MainText"> as the output <para>). As a reductio ad absurdum, I could simply have wrapped your output example in a <xsl:template> element (literal text and all !) and called that a valid solution to the stated question. You see the problem ? <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="[URL]http://www.w3.org/1999/XSL/Transform[/URL]" xmlns:xlink="[URL]http://www.w3.org/1999/xlink[/URL]" exclude-result-prefixes="xlink" <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="link" > <link href="{@xlink:href}" ><xsl:value-of select=".//text()" /></link> </xsl:template> <xsl:template match="par[@class='Normal']" /> <xsl:template match="par[@class='MainText']" > <para> <xsl:value-of select="translate (parent::item/@numberingtext, ' ', ' ')" /> <xsl:apply-templates select="* | text()" /> </para> </xsl:template> <xsl:template match="par[@class and not (@class = 'Normal' or @class = 'MainText')]" > <xsl:element name="{./@class}" ><xsl:value-of select="text()" /></xsl:element> </xsl:template> <xsl:template match="document/part" > <root> <xsl:apply-templates select="*" /> </root> </xsl:template> </xsl:stylesheet> [/QUOTE]

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