A question regarding argv

[Logan]

(CODE I)
#include <stdio.h>

int main(int argc, char *argv[])
{
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}


(CODE II)
#include <stdio.h>

int main(int argc, char *argv)
{
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}

CODE I works but CODE II gives segmentation error. Why?

 

[CBFalconer]

(CODE I)
#include <stdio.h>

int main(int argc, char *argv[]) {
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}

(CODE II)
#include <stdio.h>

int main(int argc, char *argv) {
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}

CODE I works but CODE II gives segmentation error. Why?

You want "char **argv".

 

[Barry Schwarz]

(CODE I)
#include <stdio.h>

int main(int argc, char *argv[])
{
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}


(CODE II)
#include <stdio.h>

int main(int argc, char *argv)
{
int x;

printf("argc = %d\n", argc);
for(x = 0; x < argc; x++ ) {
printf("argv[%d] = %s.\n", x, argv[x]);
}
return 0;
}

CODE I works but CODE II gives segmentation error. Why?

Because this is the same code you posted three minutes ago.


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