G
Guest
First of all thanks for helping me out.
I have to admit I dont understand some of your suggestiosn, sorry.
I dont know what is the "3D" thing... Is there another way to make it
work something more simple for a newbie like me? Thanks
What I want to do is:
First check all the files from a folder and analyze only the one with the .Seq extension.
What I want to do is to get the reverse complement of the DNA sequence. If their is a problem
with some characters in the DNA Sequence I want the function to tell it to me.
Here are the comp and iupac:
iupac ="GgAaTtCcRrYyMmKkSsWwHhBbVvDdNn"
comp={"A":"T", "T":"A", "G":"C", "C":"G", "R":"Y", "Y":"R", "M":"K",
"K":"M", "S":"W", "W":"S", "B":"V", "V":"B", "D":"H", "H":"D", "r":"y",
"y":"r", "m":"k", "k":"m", "s":"w", "w":"s", "b":"v", "v":"b", "d":"h",
"h":"d", "a":"t", "t":"a", "g":"c", "c":"g", "N":"N","n":"n"}
So if a $ or Z appears in the DNA sequence, I want to know it.
My code so far:
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *
ab1seq = raw_input("Entrez le répertoire où sont les fichiers à analyser: ") or None
if ab1seq == None :
print "Erreur: Pas de répertoire! \n" \
"\nAu revoir \n"
sys.exit()
listrep = os.listdir(ab1seq)
#print listrep
extseq=[]
for f in listrep:
if f[-4:]==".Seq":
extseq.append(f)
#print extseq
for x in extseq:
f=open(x, "r")
seq=f.read()
f.close()
#s=seq
def checkDNA(seq):
"""Retourne une liste des caractères non conformes à l'IUPAC."""
junk=[]
for c in range (len(seq)):
if seq[c] not in iupac:
junk.append([seq[c],c])
#print junk
print "ATTN: Il y a le caractère %s en position %s " % (seq[c],c)
if junk == []:
indinv=range(len(seq))
indinv.reverse()
resultat=""
for i in indinv:
resultat +=comp[seq]
return resultat
seq=checkDNA(seq)
-------------------------------------------------------------------------------------------------------------------------
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Subject: Re: problem with the logic of read files
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will appreciate it.
read.
###### It would be simplest to process each file as it is read:
@@@@@@ seq=3Df.read()
@@@@@@ checkDNA(seq)
##### The program segment you posted did not define "comp" or "iupac",
##### so it's a little hard to guess how it's supposed to work. It
would
##### be helpful if you gave a concise description of what you want the
##### program to do, as well as brief sample of input data.
##### I hope this helps! -- George
'B1-19_win3F_F04_12.ab1.Seq']
'B1-19_win3F_F04_12.ab1.Seq', 'B1-19_win3R_G04_14.ab1.Seq',
'B90_win3F_H04_16.ab1.Seq', 'B90_win3R_A05_01.ab1.Seq',
'DL2-11_win3F_H03_15.ab1.Seq', 'DL2-11_win3R_A04_02.ab1.Seq',
'DL2-12_win3F_F03_11.ab1.Seq', 'DL2-12_win3R_G03_13.ab1.Seq',
'M7757_win3F_B05_03.ab1.Seq', 'M7757_win3R_C05_05.ab1.Seq',
'M7759_win3F_D05_07.ab1.Seq', 'M7759_win3R_E05_09.ab1.Seq',
'TCR700-114_win3F_H05_15.ab1.Seq', 'TCR700-114_win3R_A06_02.ab1.Seq',
'TRC666-100_win3F_F05_11.ab1.Seq', 'TRC666-100_win3R_G05_13.ab1.Seq']
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCAAAACGTTTTTAG=
AATACTTGAACGTGTAATCTCATTTTAA
**********End Of Post*************
I have to admit I dont understand some of your suggestiosn, sorry.
I dont know what is the "3D" thing... Is there another way to make it
work something more simple for a newbie like me? Thanks
What I want to do is:
First check all the files from a folder and analyze only the one with the .Seq extension.
What I want to do is to get the reverse complement of the DNA sequence. If their is a problem
with some characters in the DNA Sequence I want the function to tell it to me.
Here are the comp and iupac:
iupac ="GgAaTtCcRrYyMmKkSsWwHhBbVvDdNn"
comp={"A":"T", "T":"A", "G":"C", "C":"G", "R":"Y", "Y":"R", "M":"K",
"K":"M", "S":"W", "W":"S", "B":"V", "V":"B", "D":"H", "H":"D", "r":"y",
"y":"r", "m":"k", "k":"m", "s":"w", "w":"s", "b":"v", "v":"b", "d":"h",
"h":"d", "a":"t", "t":"a", "g":"c", "c":"g", "N":"N","n":"n"}
So if a $ or Z appears in the DNA sequence, I want to know it.
My code so far:
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *
ab1seq = raw_input("Entrez le répertoire où sont les fichiers à analyser: ") or None
if ab1seq == None :
print "Erreur: Pas de répertoire! \n" \
"\nAu revoir \n"
sys.exit()
listrep = os.listdir(ab1seq)
#print listrep
extseq=[]
for f in listrep:
if f[-4:]==".Seq":
extseq.append(f)
#print extseq
for x in extseq:
f=open(x, "r")
seq=f.read()
f.close()
#s=seq
def checkDNA(seq):
"""Retourne une liste des caractères non conformes à l'IUPAC."""
junk=[]
for c in range (len(seq)):
if seq[c] not in iupac:
junk.append([seq[c],c])
#print junk
print "ATTN: Il y a le caractère %s en position %s " % (seq[c],c)
if junk == []:
indinv=range(len(seq))
indinv.reverse()
resultat=""
for i in indinv:
resultat +=comp[seq]
return resultat
seq=checkDNA(seq)
-------------------------------------------------------------------------------------------------------------------------
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From: (e-mail address removed)
Newsgroups: comp.lang.python
Subject: Re: problem with the logic of read files
Date: 12 Apr 2005 10:47:17 -0700
Organization: http://groups.google.com
Lines: 104
Message-ID: <[email protected]>
References: <[email protected]>
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biologist and I ma trying to learn python. So if someone can help me, II am new to python and I am not in computer science. In fact I am a
will appreciate it.
###### Minor -- this is better said as: if f.endswith(".Seq"):Thanks
#!/cbi/prg/python/current/bin/python
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *
ab1seq =3D raw_input("Entrez le r=E9pertoire o=F9 sont les fichiers =E0 analyser: ") or None
if ab1seq =3D=3D None :
print "Erreur: Pas de r=E9pertoire! \n"
"\nAu revoir \n"
sys.exit()
listrep =3D os.listdir(ab1seq)
#print listrep
extseq=3D[]
for f in listrep:
###### seq=3D... discards previous data and refers only to that justif f[-4:]=3D=3D".Seq":
extseq.append(f)
# print extseq
for x in extseq:
f =3D open(x, "r")
read.
###### It would be simplest to process each file as it is read:
@@@@@@ seq=3Df.read()
@@@@@@ checkDNA(seq)
seq=3Df.read()
f.close()
s=3Dseq
def checkDNA(seq):
"""Retourne une liste des caract=E8res non conformes =E0 l'IUPAC."""
junk=3D[]
for c in range (len(seq)):
if seq[c] not in iupac:
junk.append([seq[c],c])
#print junk
print "ATTN: Il y a le caract=E8re %s en position %s " % (seq[c],c)
if junk =3D=3D []:
indinv=3Drange(len(seq))
indinv.reverse()
resultat=3D""
for i in indinv:
resultat +=3Dcomp[seq]
return resultat
seq=3DcheckDNA(seq)
print seq
##### The program segment you posted did not define "comp" or "iupac",
##### so it's a little hard to guess how it's supposed to work. It
would
##### be helpful if you gave a concise description of what you want the
##### program to do, as well as brief sample of input data.
##### I hope this helps! -- George
function even if more files is in extseq#I got the following ( as you see only one file is proceed by the
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq']['B1-11_win3F_B04_04.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq', 'B1-18_win3F_D04_08.ab1.Seq']
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq',['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-19_win3F_F04_12.ab1.Seq']
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq',..
['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-19_win3F_F04_12.ab1.Seq', 'B1-19_win3R_G04_14.ab1.Seq',
'B90_win3F_H04_16.ab1.Seq', 'B90_win3R_A05_01.ab1.Seq',
'DL2-11_win3F_H03_15.ab1.Seq', 'DL2-11_win3R_A04_02.ab1.Seq',
'DL2-12_win3F_F03_11.ab1.Seq', 'DL2-12_win3R_G03_13.ab1.Seq',
'M7757_win3F_B05_03.ab1.Seq', 'M7757_win3R_C05_05.ab1.Seq',
'M7759_win3F_D05_07.ab1.Seq', 'M7759_win3R_E05_09.ab1.Seq',
'TCR700-114_win3F_H05_15.ab1.Seq', 'TCR700-114_win3R_A06_02.ab1.Seq',
'TRC666-100_win3F_F05_11.ab1.Seq', 'TRC666-100_win3R_G05_13.ab1.Seq']
listing (TRC666-100_win3R_G05_13.ab1.Seq)NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCAAAACGTTTTTAG=after this listing my programs proceed only the last element of this
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCAAAACGTTTTTAG=
AATACTTGAACGTGTAATCTCATTTTAA
**********End Of Post*************