Behaviour of os.rename()

[venutaurus539]

Hello all,
I got a suspicion on the behaviour of os.rename
(src,dst).If the src is the path of a file and dst is a new filename
this os.rename() function is infact creating a new file with the dst
name in the current working directory and leaving the src as it is. Is
this the expected behavior? If i want the actual source file in its
orignal location to be renamed without doing os.chdir() to that
directory, is that possible?

Ex: if my script ren.py contains the following code:

os.rename("C:\\Folder1\\Folder2\\file1,file2)

and my ren.py is in the folder D:\. Now if I run this
script, it is creating file2 in D:\ but I want it in C:
\Folder1\Folder2. is that possible?

When I checked the normal Windows rename function, it is
working to my expectations but I can't use it because my file is in a
deep path (>255) which Windows won't support.

Thanks in advance,
Venu.

 

[Tim Golden]

Hello all,
I got a suspicion on the behaviour of os.rename
(src,dst).If the src is the path of a file and dst is a new filename
this os.rename() function is infact creating a new file with the dst
name in the current working directory and leaving the src as it is. Is
this the expected behavior? If i want the actual source file in its
orignal location to be renamed without doing os.chdir() to that
directory, is that possible?

Ex: if my script ren.py contains the following code:

os.rename("C:\\Folder1\\Folder2\\file1,file2)

and my ren.py is in the folder D:\. Now if I run this
script, it is creating file2 in D:\ but I want it in C:
\Folder1\Folder2. is that possible?

When I checked the normal Windows rename function, it is
working to my expectations but I can't use it because my file is in a
deep path (>255) which Windows won't support.

os.rename on windows calls the Windows MoveFile API:

http://msdn.microsoft.com/en-us/library/aa365239(VS.85).aspx

Have a look at the details on that page to see what
the limitations / actions are. But remember -- as I've
indicated elsewhere -- to use the ur"\\?\c:\..." form
of the file names.

And let us know if that works

TJG

 

[Emile van Sebille]

Hello all,
I got a suspicion on the behaviour of os.rename
(src,dst).If the src is the path of a file and dst is a new filename
this os.rename() function is infact creating a new file with the dst
name in the current working directory and leaving the src as it is. Is
this the expected behavior? If i want the actual source file in its
orignal location to be renamed without doing os.chdir() to that
directory, is that possible?

Ex: if my script ren.py contains the following code:

os.rename("C:\\Folder1\\Folder2\\file1,file2)

os.rename("C:\\Folder1\\Folder2\\file1","C:\\Folder1\\Folder2\\file2")

Emile

 

[venutaurus539]

os.rename on windows calls the Windows MoveFile API:

 http://msdn.microsoft.com/en-us/library/aa365239(VS.85).aspx

Have a look at the details on that page to see what
the limitations / actions are. But remember -- as I've
indicated elsewhere -- to use the ur"\\?\c:\..." form
of the file names.

And let us know if that works

TJG

That actually was an illustration. As you've told in another chain, it
isn't working even after appending "\\?\"

Thank you,
Venu

 

[venutaurus539]

os.rename("C:\\Folder1\\Folder2\\file1","C:\\Folder1\\Folder2\\file2")

Emile

Thank you,
It worked