B
btrower
Can you determine output of following one liner by visual inspection..
It had won an award in obfuscated C contest.....
main() { printf(&unix["\021%six\012\0"],(unix)["have"]+"fun"-0×60);}
You can also list your favourite one liner...
What you supplied does not work with every compiler. The following
should be better:
main(){printf(&1["\021%six\012\0"],(1)["have"]+"fun"-0x60);}
If you don't understand it, that will at least give you the answer.